When testing for iodide with silver nitrate, what precipitate color would you expect?

When testing for iodide with silver nitrate, what precipitate color would you expect?

• A. White
• B. Cream
• C. Yellow
• D. Red

Answer: (C)

When testing for iodide ions using silver nitrate, the expected precipitate is a bright yellow color. This is due to the formation of silver iodide (AgI), which is a poorly soluble compound that precipitates out of the solution. The interaction occurs when silver nitrate is added to a solution containing iodide ions; the silver ions (Ag+) from the silver nitrate react with iodide ions (I-) to form the yellow precipitate of silver iodide. Silver iodide is known for its distinctive yellow color, which differentiates it from the precipitates formed with other halides. For example, silver chloride forms a white precipitate, while silver bromide results in a cream-colored precipitate. These differences in color are important for qualitative analysis in chemistry, allowing chemists to identify the presence of specific halides based on the color of the precipitate formed.

When testing for iodide ions using silver nitrate, the expected precipitate is a bright yellow color. This is due to the formation of silver iodide (AgI), which is a poorly soluble compound that precipitates out of the solution. The interaction occurs when silver nitrate is added to a solution containing iodide ions; the silver ions (Ag+) from the silver nitrate react with iodide ions (I-) to form the yellow precipitate of silver iodide.

Silver iodide is known for its distinctive yellow color, which differentiates it from the precipitates formed with other halides. For example, silver chloride forms a white precipitate, while silver bromide results in a cream-colored precipitate. These differences in color are important for qualitative analysis in chemistry, allowing chemists to identify the presence of specific halides based on the color of the precipitate formed.